Or alternatively, the pythonic way to do this without the additional conditional: for lines in mobs: Here’s an example: age 22 See if the person is 18 or not if age 18: print ('Youre old enough to drive') else: print ('You may be too young to drive, '+ 'or already older than 18. If same, it returns False and if not same, it returns True.
Whereas is not operator checks whether id () of two objects is same or not. It returns True if operands on either side are not equal to each other, and returns False if they are equal.
#Python not equal in if statement code#
If not found: # if a match wasn't found in list, print this If/else statement example When an if/else statement tests for equality, there’s also a code path that runs when the tested tested values are not the same. In Python is defined as not equal to operator. The correction would be: for lines in mobs: As you said, you only want to print not a match "if ALL of them are false" so your print statement can't be in the loop because you are not done checking all of mobsdmg: That is, you can only conclude it is not a match after the for loop. not (A and B), as the interpreter evaluates fewer logical statements, but it's trivial. Technically, it's very slightly faster to use the latter, e.g. Some programming languages also have switch or case statements that can be used for control flow. (not A) and (not B) is equivalent to not (A or B), and (not A) or (not B) is equivalent to not (A and B).
You can also do a crude type of control flow using exception handling, although that is usually not recommended. The issue in your code is that you can only print that the item is not a match after searching through all of the mobsdmg list. In Python, you can control the flow of your program using if, elif and else statements. Boolean Comparison Operators test if two values are equal (2 equals signs together).
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